2 years ago

Help ASAP please need it rn !!!

1 answer:

Leto [7]2 years ago

6 0

I think maybe it’s C???

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Gnoma [55]

Z=Xk228=12kk=228/12k=19Z=18*19Z=342 57=3k57/3=k19=k again Z=8*19Z=152
hope i could help :)

6 0

2 years ago

Amanda [17]

Are theese questions or your answers

if there answers they seem all right

7 0

2 years ago

malfutka [58]

They are multiplis of 9

4 0

2 years ago

Licemer1 [7]

117.93 is greater than 117.859 by .035.

3 0

2 years ago

Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

3 0

1 year ago