Answer:
60
Step-by-step explanation:
so 4 of BC will make a AB, so AC =5 of BC =75
therefore BC=75/5=15
If BC=15 and AB=4*BC=4*15=60
Since every figure repr. an equil. triangle, each of the angles shown is 60 deg.
Thus, the height of one of the shaded triangles is s sin 60 deg, or s/sqrt(3).
The base of one such triangle is s/3.
Thus, the area of ONE shaded triangle is A = bh/2, which here is
(s/3)(s/sqrt(3) ) (s/3)(s)
A = ----------------------- = --------------------
2 2sqrt(3)
Rationalize the denom.: Mult numerator and denominator both by sqrt(3), and then mult the resulting numerator and den by 3:
sqrt(3) s^2/3 s^2*sqrt(3) s^2*sqrt(3)
----------- * ----------- = ----------------- = ----------------
sqrt(3) 2sqrt(3) 3*2*3 18
Unfortunately, this does not agree with any of the four answer choices.
Let's take a slightly different approach here:
Each (horizontal) base of each shaded triangle has length s/3. Each has height (s/3)sin(60 deg) = s*sqrt(3)/(3*2) = s*sqrt(3)/6.
[s/3]*[s*sqrt(3)]/6
Then each shaded triangle has area A = bh/2 = ----------------------------
2
and the total shaded area is three times that:
s^2 * sqrt(3) s^2*sqrt(3)
Total area = -------------------- = ------------------ (answer)
3*2 * 6 36
Answer:
The probability of being older than 25 years and having a hemoglobin level above 11 is 19.58%. Since the question is referring to persons older than 25 years, we'll include all the data above 25 years.
So under 25-35 years old is 44 and under 35 years old is 40.
44 + 40 = 84
84 / 429 = 0.1958 or 19.58%
The probability of having a hemoglobin level above 11 is 35.66%. We would just get the ratio of 153 people who have hemoglobin level above 11 over the population of 429. 153 / 429 = 0.356643 or 35.66%
Being older than 25 years and having a hemoglobin level above 11 is not dependent on each other. Since the data is inversely proportional. The older the person gets, the lesser the number of people having hemoglobin level above 11 (A) 19.58%.
I hope this helps!
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Hello,
if n=15: (4,1),(31,8),(244,63)
if n=7: (8,3),(127,48),(2024,765)
if n=99: (10,1),(199,20),(3970,399)
(Pell 's equation)
