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Nutka1998 [239]
3 years ago
8

You buy a used car for $10,000. The value of the car decreases by22% each year. Approximately how much is the car worth in 3 yea

rs?
Mathematics
1 answer:
IRINA_888 [86]3 years ago
6 0

Answer:

The value will be $3,400 after 3 years

Step-by-step explanation:

Convert the percentage into the cash decrease each year, multiply that by 3 and then subtract $10,000 by the sum.

.22 x 10,000 = 2,200

2,200 x 3 = 6,600

10,000 - 6,600 = 3,400

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What is 204 thousands
max2010maxim [7]
204 thousands equals to 204, 000 as the mathematical value and expression. 

In expanded form 
200, 000 + 4, 000 = 204, 000 

In word form, 
Two hundred and four thousand 
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3 years ago
Um i need help with this.
blsea [12.9K]

Answer:

None of these!

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0
2 years ago
What does it equal? And how do you know that
zvonat [6]
You can cancel if the top and bottom are both multiplication and they have common factors.

Don't forget to vote brainliest and follow me!!!

4 0
3 years ago
Which of the following statements does not represent the same value as the others?
Semmy [17]

the distance between 0 and −9

the absolute value of negative 9

the opposite of 9

the absolute value of 9

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