It is now twenty-three minutes past six. What time will it be in six hours and sixteen minutes?

The number of State Parks in California is 36 more than one third the number of State Parks in Florida. There are 85 State Parks

Ber [7]

C = 1/3f + 36
c = 85

1/3f + 36 = 85 <===

5 0

3 years ago

2.2 The following data show the distances (in miles) from the homes of off-campus statistics students to the college. Create a s

Liula [17]

Answer:

Step-by-step explanation:

From the given set of data,

Stem-leaf plot will be,

Stem Leaf

0 5 7

1 1 2 2 3 3 5 5 7 7 8 9

2 0 2 5 6 8 8 8

3 5 8

4 4 8 9

5 2 5 7 8

6

7

8 0

Key for the given stem and leaf plot → 0 | 5 = 0.5

8 0

2 years ago

Clint’s salary increased from $20,000 to $32,000 over a three year period. Helen’s salary increased from 27,000 to $43,200 over

MakcuM [25]

Helens increases more over time
Clints salary increases 4000$ a year
Helens salary increases 5400$ a year
How i got that was i got there current wage subtracted it from there starting wage and then divided by 3 because it has been 3 years since the beginning wage
In 10 years if this rate continues clint would be makin 60,000$ for that year and helen would be makin 81,000$ for that year

7 0

2 years ago

If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to

LUCKY_DIMON [66]

See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

D is midpoint of BC, thus D is at (4,-7)

The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

To prove area of triangle CPQ is 1/4 area of ABC will be;

Find area ABC and CPQ then compare the areas.

Apply the distance formula to find the length of sides of the triangles then find the areas.

The distance formula is;

$d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}$

Length of side AB from the sketch is;

$AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units$

Length of side BC will be;

$BC=\sqrt{(-7--7)^2+(6-2)^2} =\sqrt{4^2} =\sqrt{16} =4units$

Thus area of triangle ABC will be;

1/2 *base length*height ------because it is a right-triangle

1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

Length of side PQ is half that of side BC thus PQ=2 units

Length of side PC is;

$PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units$

Length of side QC will be;

$QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}$

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c) where;

A=area of the triangle

s= half the perimeter of the triangle

a=side PQ = 2 units

b=side PC = 5 units

c= side QC = 3.6 units

Finding the perimeter of triangle CPQ will be;

P=sum of all sides

P=2+5+3.6 =10.6 units

s=10.6/2 = 5.3

Area of the triangle CPQ will be;

$A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98$

A=3.0 (1 decimal place)

Compare the areas;

Area of triangle ABC=12 square units

Area of triangle CPQ = 3 square units

Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

#LearnwithBrainly

6 0

2 years ago

I really need help on #51

4vir4ik [10]

That's what I did and since the zeros would be -5 and 3 the answer would be 3 since it can't be a negative

5 0

2 years ago