Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
Using product rule;
f(x)=(1+6x²)(x-x²)
f'(x)=(12x)(x-x²) + (1-2x)(1+6x²) = 12x² -12x³ +1 +6x² -2x -12x³ = -24x³ +18x² -2x +1
Solving the bracket first;
f(x)=(1+6x²)(x-x²) = x -x² +6x³ -6x^4
f'(x)= 1 -2x +18x² -24x³ = -24x³ +18x² -2x +1
Answer: 8(4) - 10 equals to 22 :)
Answer:
Step-by-step explanation:
Just give me the answer
<h3>
Answer: 82</h3>
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Explanation:
Let A be the tens digit and B be the units digit
We can write the number as AB. So if A = 9 and B = 2 for instance, then the number is AB = 92. Keep in mind I'm not multiplying A and B here.
"The unit digit is a prime" means B could be any of these values {2,3,5,7}. We only list the single digit primes. The value 1 is not prime.
Now multiply each of those items by 4
4*2 = 8
4*3 = 12
4*5 = 20
4*7 = 28
Of those results, only 4*2 = 8 leads to a single digit answer.
This must mean that A = 8 and B = 2
Therefore the number is AB = 82.
