Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Answer: It would be x^2 I think
Answer:
The smaller number equals 12, the larger number equals 51.
Step-by-step explanation:
x + (3x + 15) = 63
Combine like terms.
4x + 15 = 63
Subtract 15 from both sides.
4x + (15 -15) = (63 - 15)
4x = 48
Divide both sides by 4.
4x/4 = 48/4
x = 12
Check answer.
12 + (3(12) + 15) = 63
12 + 36 + 15 = 63
63 = 63
Answer: income
Step-by-step explanation:
Answer:
2083
Step-by-step explanation:
Every yard is 3 feet so divide 6243 ft by 3 to get your answer
Hope I helped! :)
