Please help me with this question
2 answers:
You might be interested in
6x² + 2x - 20 = 0
3(2x² + x - 10) = 0
3[(2x² - 4x + 5x - 10)] = 0
3[2x(x - 2) + 5(x - 2)] = 0
3(2x + 5)(x - 2) = 0
3=0, 2x + 5 = 0, x - 2 = 0 (Note: 3=0 is false so disregard that equation)
x = , x = 2
Answer: x = {, 2}