Answer:
0.0326 = 3.26% probability that she is a student.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Woman developer
Event B: Student
Probability that the developer is a woman:
7.4% of 25.8%(students).
76.4% of 100 - 25.8 = 74.2%(not students). So

Student and woman developer.
7.4% of 25.8%(students), so

If we encounter a woman developer, what is the probability that she is a student

0.0326 = 3.26% probability that she is a student.