Segment AE is congruent to segment EB
1 answer:
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Answer:
C' (-4 , 2)
slope of new line = line "L" = -2
Step-by-step explanation:
C (x₀,y₀): (0,2) dilation center (h,k): (2,2) scale factor (sf): 3
C' (x,y)
x = 2 + 3*(0-2) = -4 x = h + sf*(x₀ - h)
y = 2 + 3*(2-2) = 2 y = k + sf*(y₀ - k)
C' (-4 , 2)
slope of new line = line "L" = -2
