2 years ago

What is the slope of the line that passes through the points (5, -11)and (-9, 17)

Mathematics

1 answer:

Mariulka [41]2 years ago

7 0

Answer:

(17+11)/(-9-5)= 28/-14= -2 is the slope

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Help for brainliest answer

guajiro [1.7K]

Step-by-step explanation:

SA=ph+2A, that is, perimeter × height+ twice area

p=21+20+29=70cm

h=22cm

70×22=1540cm

A=1/2 ×20×21=210×2=420

1540+420=1960cm2

8 0

2 years ago

The system has......

Flura [38]

Answer:

No solution

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D

-Dominant- [34]

By iteratively substituting, we have

$a_n = a_{n-1} + n$

$a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)$

$a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)$

and the pattern continues down to the first term $a_1=0$ ,

$a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))$

$\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)$

$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

$\displaystyle \sum_{n=1}^N 1 = N$

$\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2$

It follows that

$a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2$

$\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1$

$\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}$

4 0

2 years ago

In rhombus fmkw mk=12 fk= 16 m

gizmo_the_mogwai [7]

If it is area your looking for.

Area = product of diagonal lengths divided by 2

Area = 12* 16 /2

=192/2 = 96.

IF it is the side length of the rhombus:

apply Pythagoras theorem since the diagonals always meet at 90°.

L =√(12² + 16²)

L= √400 = 20

4 0

3 years ago

What equation represents this sentence? 5 less than a number is 12. n−5=12 5=12−n 5=n−12 5−n=12

Lana71 [14]

Answer:

n-5=12

This is the answer

8 0

2 years ago