Answer:
The solution code is written in Python
- def largerThanN(myList, n):
- output = ""
-
- for x in myList:
- if(x > n):
- output += str(x) + " "
-
- print(output)
-
- l = [5, 12, 11, 4, 56, 32]
- n = 15
- largerThanN(l, n)
Explanation:
Firstly, create a function largerThanN that accepts two arguments, a list (myList) and a number (n) (Line 1).
Next, create a output variable to hold the string of numbers in the list that are greater than the input number n (Line 2).
Create a for loop to traverse through each number in the list and then check if the current x is bigger than n. If so concatenate the x to output string along with a single space " " (Line 4 -6)
After the loop, print the output string (Line 8)
We test the function by using a sample list and n = 15 (Line 10 - 12). The program will display 56 32 .
Answer:
The owls population increased by 13 in one year
Explanation:
The given data on the owl population are as follows;
The number of new owls born = 20 (positive increase in population)
The number of owls that die = 10 (negative decrease in population)
The number of owls that enter the forest = 5 (positive increase in population)
The number of owls that left the forest = 2 (negative decrease in population)
Let 'w' represent the number of new owls born, let 'x' represent the number of owls that die, let 'y' represent the number of owls that enter the forest and let 'z' represent the number of owls that left the forest, we get;
The change in population, ΔP = w - x + y - z
By plugging in the values, we get;
ΔP = 20 - 10 + 5 - 2 = 13
The change in the population of owls in one year is an increase in 13 owls.
Int j;
j="name"[4];
// you could do
j=0; // since name has four letters the fifth character is the terminating 0
now if the string name is name
you could do
j=name[4]; // or even 4[name]
Hi!
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I would have originally said facebook, but due to recent policy changes that would not be my first choice.
-<span>ASIAX </span><span> </span><span>Frequent Answerer</span>
