Answer:
an = 1/2 (4)^ (n-1)
a6 = 512
Step-by-step explanation:
The formula for a geometric sequence is
an = a1 (r)^(n-1)
where an is the term of the sequence
a1 is the initial term of the sequence
r is the ratio
and n is the term number
We know a1 = 1/2 and r =4
I will assume that x=6 means we want to know the 6th term
an = 1/2 (4)^ (n-1)
We want to find the 6th term
a6 = 1/2 * 4^(6-1)
a6 = 1/2 * 4^5
a6 = 512
The answer is 25. To check 10/.4 is 25 and 0.4 equals to 2/5
f(x) increase by a factor of 3
Explanation:
Given that f(x)= 3* and the interval is x=4 to x=57
Now we put the value for x is 4 to 57 then value of f(x) increase with the multiply of 3.
Because the x is multiplied with 3 i.e., 3*
So f(x) increase by a factor of 3.
If we put x=4, then f(x)= 12 (∵ 3×4=12)
If we put x=5, the f(x)= 15 (∵ 3×5=15)
If we put x=6,the f(x)= 18 (∵ 3×6=18)
similarly., values of x= 7,8,9,...155.
Then,
If we put x=56, the f(x)=168
This process will continue until f(x)=171 for x=57.
<span>18,36,54,72,90</span><span> are first five multiples of </span>18<span>.</span>
A²-5a+6
to factorise you find the common numbers that add to make 5 and times to make 6
soo that means it is
(a-2) (a-3)
