I’m guessing you meant central tendency.
I’d say the mean is the best measure for period 2. This is because it doesn’t have any extremely low or high values which could distort the mean value.
If it did ie. 8, then I would choose median as it is less affected by anomalous results
Answer: the probability that exactly 5 of the 8 cherry tomatoes weigh less than 4 oz is 0.05
Step-by-step explanation:
Given that;
X has normal distribution has mean µ = 3
standard deviation σ = 2
now
P( x< 4) = P( (x-µ)/σ /(3-4)/5)
= P( z < -0.5 )
= 0.3085 {from the z-table}
X has binomial distribution with n = 8 and p = 0.3085
so P(x=5)
P(x=5) = 8C₅(0.3085)⁵ (1 - 0.3085)⁸⁻⁵
= 0.0517 ≈ 0.05
Therefore the probability that exactly 5 of the 8 cherry tomatoes weigh less than 4 oz is 0.05
Answer: The probability that the fruit is an orange or a pear is 
.
Step-by-step explanation:
Given : Emily has 12 fruits in her bowl.
She has 3 apples, 5 bananas, 1 pear and 3 oranges.
A fruit is selected at random.
P(orange) = 
P(pear)= 
Since both events of selecting orange and pear are mutually exclusive , so
The probability that the fruit is an orange or a pear = P(orange) + P(pear)
Therefore , the probability that the fruit is an orange or a pear is .
You add 70 + 50 then you multiply it by 7.5 and you get, 900 gallons.
I don’t know if you can solve it since it is an expression?
