What you see in the z score table is P(z< a constant), for P( z≥ a number), subtract the probability from 1:
1-0.1587=0.8413
on the z score table, you will see that p(z<1.00)=0.8413
so c=1.00
For this case we have the following inequality:
2 ≥ 4 - v
The first thing we must do in this case is to clear the value of v.
We have then:
v ≥ 4 - 2
v ≥ 2
Therefore, the solution set is given by:
[2, inf)
Answer:
See attached image.
Answer:
0.3907
Step-by-step explanation:
We are given that 36% of adults questioned reported that their health was excellent.
Probability of good health = 0.36
Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.
Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.
i.e. 
Formula :
p is the probability of success i.e. p = 0.36
q = probability of failure = 1- 0.36 = 0.64
n = 11
So, 



Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907
Answer:
132 students
Step-by-step explanation:
100% means all of something, so 100% can also be written as 1.00
Since we need 55% of 240, we can multiply 240 by 0.55 and get 132.
Answer: 12
Step-by-step explanation: