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AysviL [449]
3 years ago
8

Please help

Mathematics
1 answer:
Rudiy273 years ago
5 0
It would be C since a scale factor of 2 makes the original A coordinate of (3,3) times 2 therefore the new coordinates being (6,6)
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Find cos(a) in the triangle.
kakasveta [241]
What triangle? you need to show the triangle
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3 years ago
PLEASE HELP FAST <br><br>WILL MARK BRAINLIST
liq [111]

Answer:

1, (c) 2,(c) 3,(a)

Step-by-step explanation:

1, f (x) = 2-x and f(2) = 2-2

for example f(-4) = 2-(-2) = 0

=4

3, 120° - 60° = 60

5 0
2 years ago
An entity with two multivalued attributes will be mapped as how many relations
grigory [225]
There are so many relationships between the original entity and new relation. 
The relation mapped from an entity involved in a 1:1 unary relationship contains a foreign key that correspond to its own primary key. 1 to one foreign key will be unique.
5 0
3 years ago
1. A right triangle is shown below. Use the Pythagorean Theorem to determine the lengths of each side. Phythagorean Theorem: a2
erik [133]
This may not be very pretty.
(2x + 5) * (2x + 5) expanded is (use foil)
F = 4x^2
O = 2x * 5 = 10x
I = 2x + 5 = 10x
L = 25
Total = 4x^2 + 20x + 25

(x + 3)(x + 3) = x^2 + 6x + 9 by the same method

 (2x + 7)(2x + 7) = 4x^2 + 28x + 49 Same method.

4x^2 + 20x + 25 + x^2 + 6x + 9 = 4x^2 + 28x + 49
5x^2 + 26x + 34 = 4x^2 + 28x + 49 Collect everything on the left.
x^2 - 2x - 15 = 0
(x - 5)(x + 3) = 0
x + 3 will have no meaning.
x - 5 = 0
x = 5

2x + 5 = 2*5 + 5 = 15
x + 3 = 5 + 3 = 8
2x+ 7 = 2*5 +7 = 17

Check
15^2 + 8^2 = 17^2
225 + 64 = ? 289
289 = 289

a = 15 <<<<< answer
b = 8 <<<<< answer
c = 17 <<<<< answer
 


5 0
3 years ago
A ceiling light has a cross-section in the shape of a parabola. The parabola is 24 cm wide and 9 cm deep. The lightbulb is locat
Sedbober [7]

Answer:

  4 cm

Step-by-step explanation:

The equation of a parabola with its vertex at the origin can be written as ...

  y = 1/(4p)x^2

The problem statement tells us that one point on the parabola is (x, y) = (12, 9). We can put these values into the equation and solve for p, the distance from the focus to the vertex.

  9 = 1/(4p)(12^2)

  9×4/144 = 1/p = 1/4 . . . . . . . . multiply by the inverse of the coefficient of 1/p

Then p = 4, and the bulb is 4 cm from the vertex.

4 0
3 years ago
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