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Yakvenalex [24]
2 years ago
12

V+2/v + 4/3v =11 How to solve this ?

Mathematics
1 answer:
Goshia [24]2 years ago
3 0

Answer:

0.189

4.525

Step-by-step explanation:

v/1 + 2/v + 4v/3 = 11

we can eliminate denominators if we distribute 3v to each term:

3v(v/1 + 2/v + 4v/3) = 3v(11)

3v² + 6 + 4v² = 33v

7v² - 33v + 6 = 0

factor this trinomial:

there are no factors of 6 that would add to -33 so we can use the quadratic formula to solve:  (-b ± √b²-4ac) / 2a

a = 7

b = -33

c = 6

[33 ± √(-33)² - 4(7)(6)] / 2(7)

(33 ± √1089 - 168) / 14

(33 ± √921) / 14

(33 ± 30.35) / 14

(33+30.35) / 14 =  4.525

(33-30.35) / 14 =  0.189

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Option A.

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A) Solving the equations 8x+4y = -4 ....... (3)and 17x+2y =-28, we get  

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B)Solving the equations 12x + 4y = 12 ....... (4)and 21x + 2y = −36, we get  

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C) Solving the equations 6x + 8y = −36 ....... (4) and 15x + 6y = −60, we get 18x -60x = -108 -(-240) =132, ⇒-42x =132, ⇒x=-132/42

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D) Solving the equations 6x + y = 15 ....... (5) and 15x − y = −9, we get 6x +15x = 6, ⇒21x =6, ⇒x=2/7  

Therefore, the solution x=2/7  do not match with the original solution.

Therefore, option A) will have the same solution. (Answer)

4 0
3 years ago
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Answer:

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