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frez [133]
3 years ago
15

The angle of elevation of the top of a tower from two points 121 m and 144 m away from the foot of the tower on th same side are

found to be complementary. find the height of the tower.​
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

132 m

Step-by-step explanation:

Refer to attachment for figure.

In smaller triangle with angle theta , we have ,

⇒ tanθ = p/b

⇒ tanθ = h/121m

⇒ tanθ = h/121 m

<u>In</u><u> </u><u>triangle</u><u> </u><u>with</u><u> </u><u>angle </u><u>9</u><u>0</u><u>-</u><u>∅</u>

⇒ tan(90-θ) = p/b

⇒ cot θ = h/144 m

Multiplying these two ,

=> tanθ . cotθ = h/121 m × h/144m

=> 1 = h²/ (121 m × 144m )

=> h² = 121m × 144m

=> h= √ ( 121m × 144m)

=> h = 11m × 12m

=> h = 132 m

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Lines a and b are parallel

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Lines d and c are perpendicular

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Part 2) Find the slope of Line b

we have the points

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substitute in the formula

m=\frac{3+3}{-8+10}

m=\frac{6}{2}

m_b=3

Part 3) Find the slope of Line c

we have the points

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substitute in the formula

m=\frac{-4-5}{3-0}

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substitute in the formula

m=\frac{-4+7}{13-4}

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simplify

m_d=\frac{1}{3}

Part 5) Compare the slopes

Remember that

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we have

m_a=\frac{1}{3}

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therefore

Lines a and b are parallel (slopes are equal)

Lines a and c are perpendicular (slopes are opposite reciprocal)

Lines d and c are perpendicular (slopes are opposite reciprocal)

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