The angle of elevation of the top of a tower from two points 121 m and 144 m away from the foot of the tower on th same side are
found to be complementary. find the height of the tower.
1 answer:
Answer:
132 m
Step-by-step explanation:
Refer to attachment for figure.
In smaller triangle with angle theta , we have ,
⇒ tanθ = p/b
⇒ tanθ = h/121m
⇒ tanθ = h/121 m
<u>In</u><u> </u><u>triangle</u><u> </u><u>with</u><u> </u><u>angle </u><u>9</u><u>0</u><u>-</u><u>∅</u>
⇒ tan(90-θ) = p/b
⇒ cot θ = h/144 m
Multiplying these two ,
=> tanθ . cotθ = h/121 m × h/144m
=> 1 = h²/ (121 m × 144m )
=> h² = 121m × 144m
=> h= √ ( 121m × 144m)
=> h = 11m × 12m
=> h = 132 m
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