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34kurt
3 years ago
7

What is an equation of the line that passes through the points (-6, -5)(−6,−5) and (-2, 3)(−2,3)? Put your answer in fully reduc

ed form.
Mathematics
1 answer:
Alex787 [66]3 years ago
7 0

Answer:

y=1/2x-2

Step-by-step explanation:

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The distance from the center of a tire to the edge is 4 inches. How far will the tire rotate in 3 rotations
miv72 [106K]

Answer:

12 inches

Step-by-step explanation:

4 0
3 years ago
Twelve students are going roller skating. Each student pays $8 for a ticket and $4 fot snacks. Find the total cost for tickets a
solong [7]
The answer is 144. Because 8+4=12 and 12x12=144
4 0
3 years ago
Read 2 more answers
Describe in words the translation of X represented by the translation rule T ...?
Digiron [165]
<h3>Answer: B. 4 units to the right, 5 units down</h3>

The vector notation <4, -5> is the same as writing (x,y) \to (x+4, y-5) which in my opinion is more descriptive in saying "4 units to the right, 5 units down"

We shift 4 units to the right because of the x+4. Whatever x is, add 4 to it getting x+4. So for instance x = 10 leads to x+4 = 10+4 = 14.

The y-5 is why we shift 5 units down. Eg: y = 37 leads to y-5 = 37-5 = 32.

5 0
3 years ago
Write the sum using summation notation, assuming the suggested pattern continues.
mart [117]

Answer:

\sum_{n = 1} 2*(-5)^{n-1}

Step-by-step explanation:

An arithmetic sequence is of the form:

A_n = A_{n-1} + d

While a geometric sequence is of the form:

A_n = A_{n-1}*r

notice that first, we have a change of sign in our sequence, so we already can discard the arithmetic sequence.

In fact, the pattern is kinda easy to see.

The first term is:

A₁ = 2

the second term is:

A₂ = -10

notice that:

A₂/A₍ = r = -10/2 = -5

The third term is:

A₃ = 50

the quotient between the third term and the second term is:

A₃/A₂ = 50/-10 = -5

Whit this we can already conclude that the n-th term of our sequence will be:

A_n = A_{n-1}*(-5)

Then the summation will be something like:

\sum_{n = 1} A_n = A_1 + A_2 + A_3 + ... = 2 - 10 + 50 - ...

We can write:

A_n = A_{n-1}*(-5) = (A_{n-2}*(-5))*(-5)) = A_1*(-5)^{n-1} = 2*(-5)^{n-1}

Then the summation is just:

\sum_{n = 1} 2*(-5)^{n-1}

7 0
3 years ago
Algebra 1 I need help ​
Rama09 [41]

There's a bit of lack of context but I think the question is just asking what variables to put in for Lucy and Howard. There seems to be no need to answer any math problem.

I suggest using the variables x and y or l for Lucy and h for Howard. Remember to use lowercase letters.

6 0
3 years ago
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