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7nadin3 [17]
3 years ago
8

Please help I’m a bit stuck :)

Mathematics
2 answers:
Yuliya22 [10]3 years ago
5 0
The side lengths are 11
tiny-mole [99]3 years ago
3 0

Answer:

All side lengths are 11 because it is a square and all of the sides are equal. But I'm not sure about the angles

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P = 2Q + R/R. find P when R = Q​
Lisa [10]

Answer:

Step-by-step explanation:

R=Q

P=2Q+R/R

P=2R+R/R

P=3R/R

P=3

6 0
3 years ago
If a^2+1/a^2=79 where (a>0), find the value of a^3 +1/a^3
Nastasia [14]

Note the binomial expansion,

(<em>a</em> + 1/<em>a</em>)³ = <em>a</em> ³ + 3<em>a</em> + 3/<em>a</em> + 1/<em>a</em> ³

so

<em>a</em> ³ + 1/<em>a</em> ³ = (<em>a</em> + 1/<em>a</em>)³ - 3 (<em>a</em> + 1/<em>a</em>)

Similarly,

(<em>a</em> + 1/<em>a</em>)² = <em>a</em> ² + 2 + 1/<em>a</em> ²

We're given <em>a</em> ² + 1/<em>a</em> ² = 79, so

(<em>a</em> + 1/<em>a</em>)² - 2 = 79

(<em>a</em> + 1/<em>a</em>)² = 81

<em>a</em> + 1/<em>a</em> = ±9

but <em>a</em> > 0, so we ignore the negative solution.

Then

<em>a</em> ³ + 1/<em>a</em> ³ = 9³ - 3×9 = 702

7 0
3 years ago
37
lana66690 [7]

Answer:

I don't know

Step-by-step explanation:

Because you are in college and that's what it says!!

5 0
3 years ago
Identify a possible first step using the elimination method to solve the system and then find the solution to the system. 3x + 2
mrs_skeptik [129]

A) Multiply second equation by 2, solution

8 0
3 years ago
Evaluate the given integral by making an appropriate change of variables. 10 x ? 5y 8x ? y da, r where r is the parallelogram en
Artyom0805 [142]
Take

\begin{cases}u=x-5y\\v=8x-y\end{cases}

so that you have

\begin{cases}\mathbf x(u,v)=\dfrac{-u+5v}{39}\\\\\mathbf y(u,v)=\dfrac{-8u+v}{39}\end{cases}

which gives a Jacobian determinant of

|\det J|=\left|\begin{vmatrix}\mathbf x_u&\mathbf x_v\\\mathbf y_u&\mathbf y_v\end{vmatrix}\right|=\dfrac1{32}

So upon transforming the coordinates to the u-v plane, you have (and I'm guessing on what the integrand actually is)

\displaystyle\iint_R(10x-5y)(8x-y)\,\mathrm dA=\frac1{32}\int_{u=0}^{u=2}\int_{v=5}^{v=10}\frac5{13}(2u+3v)v\,\mathrm dv\,\mathrm du
=\displaystyle\frac5{416}\int_{u=0}^{u=2}\int_{v=5}^{v=10}(2uv+3v^2)\,\mathrm dv\,\mathrm du=\dfrac{2375}{104}
4 0
4 years ago
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