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3 years ago

What is x^2-1-3(2x-2)(x-2)

Mathematics

1 answer:

gayaneshka [121]3 years ago

5 0

Answer:

=−5x2+18x−13

Step-by-step explanation:

Let's simplify step-by-step.

x2−1−3(2x−2)(x−2)

Distribute:

=x2+−1+−6x2+18x+−12

Combine Like Terms:

=x2+−1+−6x2+18x+−12

=(x2+−6x2)+(18x)+(−1+−12)

=−5x2+18x+−13

Answer:

=−5x2+18x−13

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What is the range of this set of heights in centimeters? {140, 166, 132, 165, 152, 168, 181, 158, 173, 171, 180, 182, 163, 177,

Sholpan [36]

Answer:

Step-by-step explanation:

Given:

140, 166, 132, 165, 152, 168, 181, 158, 173, 171, 180, 182, 163, 177, 180, 142, 147, 149, 178

Arranging in ascending order (from the lowest to the highest)

= 132, 140, 142, 147, 149, 152, 158, 163, 165, 166, 168, 171, 173, 177, 178, 180, 180 181, 182

Range = highest number - lowest number

= 182 - 132

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3 years ago

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rusak2 [61]

Answer:

Step-by-step explanation:

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4 years ago

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2. To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees is selected. a. Would you

ANEK [815]

Answer:

Step-by-step explanation:

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

0.01 is less than 0.05 and hence we would not us the finite population correction factor in calculating the standard error of the mean.

Population standard deviation is σ = 8.2

So, the standard error of x’ using the finite population correction factor is give by

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

Standard error of x’ without using the finite population correction factor is

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

There is little difference between the two values of the standard error. So we can ignore the population correction factor.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

So the required probability is

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

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3 years ago

Please help. Which expression is the completely factored form of 27x^3+y^6 ?

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4 years ago

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Art [367]

Answer:

6/9

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3 years ago

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