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fenix001 [56]
3 years ago
14

What are the excluded values of the function? y= 5/6x-72​

Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer: x=12

Step-by-step explanation:

Shkiper50 [21]3 years ago
7 0

Answer:

x = 12 is the excluded value

Step-by-step explanation:

An excluded value is the value/s of x that make the denominator of the rational function equal to zero as this would make the function undefined.

Equate the denominator to zero and solve for x

6x - 72 = 0 ⇒ 6x = 72 ⇒ x = 12 ← excluded value

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Answer:

-8d+3w is the simplest form

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the first term of an arithmetic sequence is 2 and the sum of the first 15 terms is 292.5. Find the common difference
adelina 88 [10]

Given:

First term of an arithmetic sequence is 2.

Sum of first 15 terms = 292.5

To find:

The common difference.

Solution:

We have,

First term: a=2

Sum of first 15 terms: S_{15}=292.5

The formula of sum of first n terms of an AP is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Where, a is first term and d is common difference.

Putting S_{15}=292.5, n=15 and a=2 in the above formula, we get

292.5=\dfrac{15}{2}[2(2)+(15-1)d]

292.5=\dfrac{15}{2}[4+14d]

292.5=15[2+7d]

Divide both sides by 15.

\dfrac{292.5}{15}=2+7d

19.5=2+7d

19.5-2=7d

17.5=7d

Dividing both sides by 7, we get

\dfrac{17.5}{7}=d

2.5=d

Therefore, the common difference is 2.5.

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3 years ago
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Ryan and Allison want to build a ramp to help their elderly cat, Simms, walk up the bed. They
Harman [31]

Answer:

Step-by-step explanation:

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3 years ago
A hair salon completed a survey of 367 customers about satisfaction with service(Dissatisfied, Neutral, Satisfied, or Very Satis
mamaluj [8]

The results of the survey are shown in the table.

It's required to calculate the following probabilities:

a) A customer is neutral

The row labeled as 'Neutral' has a total of 79 customers out of 367 in total.

The required probability is:

p=\frac{79}{367}

b) A customer is a walk-in

The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is

p=\frac{106}{367}

c) A customer is dissatisfied and a walk-in.

We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.

The required probability is:

p=\frac{22}{367}

d) A customer is very satisfied given he saw a TV ad.

This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:

p=\frac{33}{111}=\frac{11}{37}

e) A customer is satisfied or referred.

Total satisfied = 139

Total referred = 150

With both features = 62

Total customers with one or both features: 139 + 150 - 62 = 227

We have to subtract the common feature because it was counted twice.

The required probability is:

p=\frac{227}{367}

6 0
1 year ago
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