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Mandarinka [93]
3 years ago
13

Find the area of the unshaded part of the figure

Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0
<h3>Answer:</h3>

  unshaded area = 25(4 -π) in^2 ≈ 21.46 in^2

<h3>Step-by-step explanation:</h3>

Each of the shaded circles has a diameter of (20 in)/4 = 5 in, which also is the width of the enclosing rectangle. Then each circle has a radius of 2.5 in, and an area of ...

  A = πr^2 = π(2.5 in)^2 = 6.25π in^2

The four circles together have an area of ...

  4A = 4·(6.25π in^2) = 25π in^2

The area of the rectangle is the product of its length and width:

  A = LW = (20 in)(5 in) = 100 in^2

Since the circles are shaded, the unshaded area is the difference between the rectangle area and the total area of the four circles:

  unshaded area = (100 in^2) - (25π in^2) = 25(4 -π) in^2 ≈ 21.46 in^2

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The slope is 5/4.

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3 years ago
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In 4 games, Larry averaged 23 PPG (points per game). How many points does he need to score in the last game to have an average o
ivann1987 [24]
Larry needs to score 33 points in the last game to have an average of 25 PPG.

To find the answer, we can solve the equation:

\frac{(4)23+p}{5}=25

<em />(where <em>p</em> is how many points he needs to score in the last game)

To find the mean of a group of numbers, you add them all up and divide the total by the number of numbers there are. Since Larry averaged 23 PPG in 4 games, we can multiply 23 by 4 to get the total of the first 4 games from the data. Then, we find <em>p</em>, which we will add to get our final total. Then, you divide by the 5 games.

\frac{(4)23+p}{5}=25
\frac{92+p}{5}=25
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p=33

First, I simplified 4 x 23 to get 92. Then, I multiplied each side by 5 to get rid of the denominator. Finally, I subtracted 92 from each side to isolate <em>p</em>, and found that <em>p</em> = 33.


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4 years ago
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Solve for x in the equation x squared + 2 x + 1 = 17.
Papessa [141]

Answer:

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

Step-by-step explanation:

given equation

x^2 +2x +1 = 17

subtracting 17 from both sides

x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\

the solution for quadratic equation

ax^2 + bx + c = 0 is given by

x = x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a

________________________________

in our problem

a = 1

b = 2

c = -16

x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4  + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x =  ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\

thus value of x is

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

3 0
3 years ago
44 × 20 × 10 = 440 × 2. but is it true or false ?
Vinil7 [7]
If you would like to know if 44 * 20 * 10 equals to 440 * 2, you can check it like this:

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