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2 years ago

Will give brainliest!

Mathematics

1 answer:

miv72 [106K]2 years ago

6 0

Answer:

it means that the roots of the quadratic equation is real and distinct and that means that 40 is a positive value

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It’s just 2.a answer please

Inessa05 [86]

You have to convert the 30 inches into you know what and add them all together

8 0

3 years ago

Write an equation that represents a vertical translation 7 units down of the graph of g(x) = 21.

xenn [34]

Answer:

Step-by-step explanation:

f(x) + n - translation n units up

f(x) - n - translation n units down

f(x + n) - translation n units to the left

f(x - n) - translation n units to the right

===========================================

g(x) = 21

translation 7 units down: g(x) - 7 = 21 - 7 = 14

3 0

3 years ago

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp

olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = $\overline{x}$ = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data speeds i.e. x - $\overline{x}$

x - $\overline{x}$ = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between carrier's highest data speed and the mean of all 50 data speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

$\frac{59.98}{20.03}=2.99$

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

$z=\frac{x-\overline{x}}{s}$

Using the given values, we get:

$z=\frac{75.6-15.62}{20.03}=2.99$

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the carrier's highest data speed is significantly higher.

3 0

3 years ago

If 3x^2-4x+7=0, then [x-2/3]^2=

Andrews [41]

I hope this helps you

7 0

3 years ago

A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As

Semenov [28]

Answer:

$0.2564\text{ pounds}$

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the $X$ percentile for the television weights, use the formula:

$X=\mu +k\sigma$ , where $\mu$ is the average of the set, $k$ is some constant relevant to the percentile you're finding, and $\sigma$ is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute $\mu=5$ , $k=1.282$ , and $\sigma=0.1$ :

$X=5+(1.282)(0.1)=5.1282$

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

$X=5+(-1.282)(0.1)=4.8718$

The difference between these two weights is $5.1282-4.8718=\boxed{0.2564\text{ pounds}}$ .

8 0

3 years ago

Read 2 more answers