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2 years ago

Will give brainliest!

Mathematics

1 answer:

miv72 [106K]2 years ago

6 0

Answer:

it means that the roots of the quadratic equation is real and distinct and that means that 40 is a positive value

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Instruction

natulia [17]

Answer:

Step-by-step explanation:

Your question has typographical errors. The equation is 2a + b = 15.7, not 2e+b-15.7

2a + b = 15.7

b = 15.7 - 2a

since a > b, a = 6.3 cm

b = 15.7 - 2·6.3 = 3.1 cm

3 0

2 years ago

What's P squared -1 factorised?

Aleksandr [31]

(p+1) (p-1). solved this on paper . hope it helps .

8 0

3 years ago

The random variable X is normally distributed.

Nastasia [14]

Answer:

Step-by-step explanation:

because it tje best answer on there ferl me

6 0

2 years ago

Admission tickets are $80 for adults and $50 for kids. The ration of kids to adults is 5:2. If they paid $10,000, find the numbe

Elan Coil [88]

Answer:

80 adults

Step-by-step explanation:

The number of kids is $10,000/$50 = 200. The number of adults is 2/5 of that, or 80.

There are 80 adults in the group.

4 0

2 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

2 years ago