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Maksim231197 [3]
2 years ago
6

Please help me guys I need it

Mathematics
1 answer:
baherus [9]2 years ago
4 0

Answer:

the vertex is M the sides for 2 are MQ and MP for 1 they're MN and MQ

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Solve for t. <br><br> d=3+at^2
GalinKa [24]

Answer:

it's the 2nd one

Step-by-step explanation:

d = 3 + at^2

-3 | -3

d - 3 = at^2

d - 3/a = t^2

√d - 3/a = √t^2

t = √d - 3/a

8 0
3 years ago
Describe the slope of the graph?
andreyandreev [35.5K]
Attach an image of the line on a Cartesian plane for us to help you
5 0
2 years ago
What is the volumen , in cube centimeters, if a cube with a side length, s, of 0.2cm?
Shalnov [3]

Answer:

\frac{1}{125}cm³

Step-by-step explanation:

volume of cube= (side)³

0.2³ = \frac{1}{125}

5 0
1 year ago
There are five consecutive odd integers. The sum of the three smallest is 3 more than the sum of the two largest. Find the integ
lys-0071 [83]

Answer:

The answer is "\bold{11, \ 13, \ 15, \ 17, \ 19}".

Step-by-step explanation:

In word problem, it is solved by 2k+1, among the most common forms of even an, unlike number.

Let another odd integer become 2k+1.....(a)

(2K+1)+(2k+3)+(2k+5)=(2k+7)+(2k+9)+3(to take the left side 3 extra)  

Quality for the k:

\to 6k+ 9 = 4k +19 \\\\\ \to 6k-4k= 19+9 \\\\ \to 2k = 10 \\\\ \to k = \frac{10}{2}\\\\  \to K = 5

put the value of k, in the equation (a):

\to 2k+1 \\ \to 2(5)+ 1 \\ \to 10 + 1\\\to 11\\

There are also 11, 13, 15, 17, and 19 episodes.  

Let's test it! Let's test it. 11+13+15=39  

17+ 19 = 36.  

So we're right, the first 3 integer numbers are 3 more than the last 2.

5 0
3 years ago
Hi!! Hope you help and explain how. Thank you!
Nookie1986 [14]
Here, hope this helps!

3 0
2 years ago
Read 2 more answers
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