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Vinvika [58]
3 years ago
10

C=59(F−32)

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0

Answer:

love how all our accounts got deleted. smh

Step-by-step explanation:

mestny [16]3 years ago
4 0

Answer: here u go ig

Step-by-step explanation:

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What is 2.85 centimeters in expanded form?
sattari [20]
The answer for <span>2.85 centimeters in expanded form is </span>2 centimeters+ .85 centimeters= 2.85 centimeters
5 0
3 years ago
What is the least common denominator for the fractions 1/3 and 1/6
Hoochie [10]

Answer:

least common denominator=6

Step-by-step explanation:

For the fractions, 1/3 and 1/6th, 3*2=6. making the fraction 2/6 and leaving the other the same 1/6th.

3 0
2 years ago
If z varies directly with the product of x and y(z=k x y) , then z is said to vary jointly with x and y .
Dafna1 [17]

The value of z varies jointly with w and y.

What is the constant of proportion?

A constant of proportion is illustrated as the ratio which relates two given quantities with each other in the relationship of proportion. Constant of proportion is also called constant variation, rate of change, and constant ratio.

Solving for the value of constant of variation

let k be the constant of proportion

When a quantity varies directly with others, then we have a relation, y = kx

Given relation is z = kxy        —-- 1

Also x varies directly with w i.e. x = k'w, where k' is constant of variation for x and w

Using in equation 1, we have,

z = k(k'w)y

z = kk'wy

z = Kwy, where K is constant of variation i.e. K = kk'

It shows that z varies directly with w and y.

Hence, z varies jointly with w and y.

To learn more about the constant of proportion, visit the link:

brainly.com/question/24868934

#SPJ4

5 0
1 year ago
Marissa says that lines a and d will eventually
dexar [7]

Answer:The last one :)

Step-by-step explanation

8 0
3 years ago
Read 2 more answers
Show me how you solve it
julia-pushkina [17]

Answer:

5^20

Step-by-step explanation:

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u>

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n} }

Therefore:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  }

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{( {a}^{m} ) ^{n} =  {a}^{m \times n}  }

Thus:

\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{8 - 3})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =  ({5}^{5})^{4}  } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  = {5}^{5 \times 4}   } \\  \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4}  =   {5}^{20} }

7 0
3 years ago
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