The correct answer to your question is B.
Hope this helps!
Please give brainliest
Answer:
![\sqrt[3]{62}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B62%7D)
is closest to 4.
Step-by-step explanation:
Our approach consist in comparing the given cubic root with respect to other two cubic roots consecutive to each other and whose result is an integer. The following condition must be satisfied:
![n < \sqrt[3]{62} < n+1](https://tex.z-dn.net/?f=n%20%3C%20%5Csqrt%5B3%5D%7B62%7D%20%3C%20n%2B1)
If 
, then the simultaneous inequation is observed:
Since 62 is closer to the upper bound, then is closest to 4.
<span>3a^2+9
Factor out 3
=3(a^2+3)
</span>
Answer:
See below ~
Step-by-step explanation:
<u>Part A : Center</u>
- Midpoint of diameter points
- M = (13 + 5 / 2, 10 + 16 / 2)
- M = (9, 13)
<u>Part B : Radius</u>
- Half of the distance between the points
- 16 - 10 / 2
- 6/2
- radius = 3
<u>Part C : Equation</u>
- (x - 9)² + (y - 13)² = 3²
- x² - 18x + 81 + y² - 26y + 169 = 9
- x² - 18x + y² - 26y + 241 = 0
