Help me I give you a cookie:)

Bingel [31]

1200 pennies!!!!!!!!!

8 0

4 years ago

Jasmine created this spinner to predict whether a randomly selected student in her school will be traveling during the upcoming

riadik2000 [5.3K]

Answer: 9

Step-by-step explanation:

There are 8 equal sections which are meant to reflect the data Jasmine collected from surveying the students.

This means that each section represents;

= 36/8

= 4.5 students.

There are 2 sections that represent the number of students who said they would be traveling during the holiday break.

= 4.5 * 2

= 9 students

4 0

3 years ago

Read 2 more answers

Please help! And 20 points! :3<br> I need help with these 3 questions-<br> -3-||

Katyanochek1 [597]

Answer:

18. Its 2 meters.

19. Its 0.2 grams

20. Its 1,920

Step-by-step explanation:

When you convert 200 centimeters to meters its 2.

When you convert 2,000 milligrams in grams its 0.2

15% of 12, 800 is 1,920

Hope this helps:)

8 0

3 years ago

PLS ANSWER I WILL GIVE YOU BRAINLIST AND A THANK YOU!!

Arte-miy333 [17]

Answer:

x=45

Step-by-step explanation:

2x+45+x=180

Combine 2x and x to get 3x.

3x+45=180

Subtract 45 from both sides.

3x=180−45

Subtract 45 from 180 to get 135.

3x=135

Divide both sides by 3.

x=135/3

Divide 135 by 3

x=45

8 0

3 years ago

A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco

Brut [27]

Answer:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X_{A}=48250$ represent the mean of elementary teachers

$\bar X_{B}=45630$ represent the mean for secondary teachers

$s_{A}=3900$ represent the sample standard deviation for elementary teacher

$s_{B}=5530$ represent the sample standard deviation for secondary teachers

$n_{A}=26$ sample size selected

$n_{B}=24$ sample size selected

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A}-\mu_{B}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0

3 years ago