Answer:
Let C represent the total cost of each deal
Let T be the number of trips down the water slide
C = 32 for the 1st deal since the cost is the same regardless of how much she rides
C = 18 + T for the 2nd deal
To find when the two costs are equal set them equal to each other and solve for T
32 = 18 + T
T = 14 trips
The cost must be $32 since that is the only cost possible for the 1st deal
Step-by-step explanation:
Answer:
There are 16 servings
Step-by-step explanation:
<u>First, find how many oz are in 5 quarts. </u>
<em>Think: In one quart there are 32 ounces, in 5 quarts how many ounces would that be?</em>
5 x 32 = 160 ounces
<u>Next, divide 160 ounces by 10 servings</u>
160 / 10 = 16 servings
So there are 16 servings in a 5 quart pitcher.
Hope this helps ;)
Part A.
We are given the total volume of the amount of sand she will want to fill
we are also given the shape and dimensions of the cylinders
Total volume of the sand = 1,000
Cylinder= radius 4 in, and height 8 in
the volume of a cylinder is V=πr^2h
We will solve for the volume of the cylinders
V=πr^2hV=π(4)^2*(10)
V = π (16) * (10)
V = π 160
The volume of the cylinders she wants to fill is 502.65 in^3
How many cylinders will she need
Well,
1000/502.65 <span>≈ 1.98
She will need two cylinder cans to fill with the 1,000 in^3 of sand
Part B.
To see if this is true, we find the half of the original cylinder's radius and height then solve for the volume and compare
</span>V=πr^2h
<span>The height and radius of the original cylinders were 4 r and 8h
we will find half of that which will be : 2 r and 4 h
Now solve for the volume </span>V=πr^2h
V=π(2)^2* (4)
V=π (4)*(4)
V = π 16
V ≈<span> 50.26 inches ^3
The volume of the original cylinders was </span>502.65 in^3 and the volume of the new cylinders is 50.26 in^3... Clearly the volume of the new cylinders is NOT half of the original. Sally is not correct!
<span>
Hope this helps :)
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