The answer to your question is n is equal to 70
Answer:
s(2) = 7.75
Step-by-step explanation:
given the velocity v(t) = t^3
we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.

Now we can use this value of t to formulate the position function s(t):

this is the position at time t.
to find the position at t=2



the position of the particle at time, t =2 is s(2) = 7.75
Let the base be b. Then the height is b-4. So:
1/2(b)(b-4)=6
b²-4b-12=0
(b-6)(b+2)=0
b=6
b-4=2
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The answer if less you mean subtraction is 3d2 + d + 1