HELP PLSSSSSSSS I'M LOST PLSSSSSSSSSSSSSSSSSS

Mathematics

1 answer:

pav-90 [236]3 years ago

4 0

Answer:

1. 1/4 or 25/100, .25 and 25%

2. 1/10 or 1/100, .10 and 10%

Step-by-step explanation:

25 cubes out of 100 is 25/100

Simplify to 1/4

if its 25 cubes out of 100 its gonna fill up 25% or .25 of the whole thing

10 cubes out of 100 is 10/100

then simplify to 1/10

other two are obvious lol

You might be interested in

HELP PLEASE assume that y varies inversely with x. if y=1.6 when x=0.5 find x when y=3.2

DiKsa [7]

Y=k/x
1.6=k/0.5
K=0.8
Y=0.8/x
3.2=0.8/x
X=0.8/3.2
X=0.25
Hope this helps

4 0

4 years ago

I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$