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Eva8 [605]
3 years ago
9

What is -7x+2y=-23 y=-8x+23

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0
<u>Steps:</u>I will try to solve your system of equations.
<span><span>y=<span><span>−<span>8x</span></span>+23</span></span>;<span><span><span>−<span>7x</span></span>+<span>2y</span></span>=<span>−23
</span></span></span><span>Step: Solve <span>y=<span><span>−<span>8x</span></span>+23 </span></span>for y: </span><span>Step:
Substitute<span><span>−<span>8x</span></span>+23 </span>for y in <span><span><span><span>−<span>7x</span></span>+<span>2y</span></span>=<span>−23</span></span>:
</span></span><span><span><span>−<span>7x</span></span>+<span>2y</span></span>=<span>−23</span></span><span><span><span>−<span>7x</span></span>+<span>2<span>(<span><span>−<span>8x</span></span>+23</span>)</span></span></span>=<span>−23</span></span><span><span><span><span>−<span>23x</span></span>+46</span>=<span>−23</span></span>(Simplify both sides of the equation)</span><span><span><span><span><span>−<span>23x</span></span>+46</span>+<span>−46</span></span>=<span><span>−23</span>+<span>−46</span></span></span>(Add -46 to both sides)</span><span><span>−<span>23x</span></span>=<span>−69</span></span><span><span><span><span>−<span>23x</span></span><span>−23</span></span>=<span><span>−69</span><span>−23</span></span></span>(Divide both sides by -23)</span><span>x=3</span><span>Step: Substitute 3 for x in <span><span>y=<span><span>−<span>8x</span></span>+23</span></span>:</span></span><span>y=<span><span>−<span>8x</span></span>+23</span></span><span>y=<span><span><span>(<span>−8</span>)</span><span>(3)</span></span>+23</span></span><span><span>y=<span>−1</span></span>(Simplify both sides of the equation)
</span><u>Answer:</u><span><span>y=<span>−<span><span>1<span> and </span></span>x</span></span></span>=<span>3</span></span>
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Answer:-1/6

Step-by-step explanation:

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8 0
3 years ago
A negative angle or a positive angle may be used to represent the same thing.
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Answer:

1.Sometimes

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8 0
3 years ago
2 A pharmacist has a 13 % alcohol solution and another 18 % alcohol solution. How much of each must he use to make 50 grams of a
nalin [4]
<h2>Therefore he took 40 gram of 1^{st} type solution and 10 gram of 2^{nd} type solution.</h2>

Step-by-step explanation:

Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .

Let he took x gram solution of 1^{st} type solution

and he took (50-x) gram of 2^{nd} type solution.

Total  amount of alcohol =[x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ] gram

Total amount of solution = 50 gram

According to problem

⇔\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}

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⇔- 5x= 700 - 900

⇔5x = 200

⇔x = 40 gram

Therefore he took 40 gram of 1^{st} type solution and (50 -40)gram = 10 gram of 2^{nd} type solution.

7 0
4 years ago
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KATRIN_1 [288]
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3 years ago
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frosja888 [35]

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3 0
3 years ago
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