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Bingel [31]
3 years ago
11

PLEASE HELP What is the circumference of a circle?​

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0
2 • pi • radius which is same as 2 • 3.14 • r
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Not good at this need some help
emmasim [6.3K]

Answer:

216 sq. units

Step-by-step explanation:

From the figure, we can see that only one pair of opposite angles are equal. So, the quadrilateral is a kite.

Formula to find the area of a kite:

Area, A = $ \frac{1}{2} \times d_1 \times d_2 $

where, $ d_1 $ and $ d_2 $ are the lengths of the diagonals.

Here, $d_1 = 18 $ units.

And, $ d_2 = 24 $ units.

Therefore, the area A = $ \frac{1}{2} \times 18 \times 24 $

= $ \frac{432}{2} $

= 216 sq. units which is the required answer.

6 0
3 years ago
Find the area of this triangle, round to the nearest tenth, I will give brainliest
Setler79 [48]

Answer:

59.15 in^2

Step-by-step explanation:

Using Heron's formula

semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4

Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2

4 0
1 year ago
Read 2 more answers
What is the frequency of the sinusoidal graph ?
disa [49]

Answer:

The frequency of the given sinusoidal graph is 4.

Step-by-step explanation:

The frequency of a sinusoidal graph is the number of cycles it completes in the interval 0 to 2π radians.

From the given sinusoidal graph it is noticed that the the graph complete its one cycle in the interval 0 to \frac{\pi}{2}.

If the complete its one cycle in \frac{\pi}{2}, then the number of cycles completed by the graph in the inteval 0 to 2π is

\frac{\pi}{2}\times frequency=2\pi

frequency=2\pi \times \frac{2}{\pi}

frequency=4

Therefore the frequency of the given sinusoidal graph is 4.

7 0
3 years ago
A new truck costs $32,000 if the truck is worth 24,500 after three years write an explicit formula for the value of the car afte
Debora [2.8K]

Answer:

Step-by-step explanation:

depreciation for three years = 32000 - 24500 = $ 7500

depreciation per year = 7500/3 = $ 2500

depreciation % = (2500/32000)*100 = 7.81%

Value of truck after n years = 32000 * (7.81%)*n

8 0
3 years ago
how many kilograms of pure water is to be added to 100 kilograms of a 30% saline solution to make it a 10% saline solution
Irina-Kira [14]

Answer:

  200 kg

Step-by-step explanation:

If w is the amount of water added, then the concentration of the solution is ...

  salt/solute = 100(0.30)/(100 +w) = 0.10

  30 = 10 +0.10w . . . . . simplify

  20 = 0.10w . . . . . . . . subtract 10

  20/0.10 = w = 200 . . . . divide by 0.10

200 kg of water must be added to dilute the solution to 10%.

4 0
2 years ago
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