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hichkok12 [17]
3 years ago
13

Using the technique in the model above, find the missing sides in this 30°-60°-90° right triangle.

Mathematics
2 answers:
valina [46]3 years ago
8 0

Answer:

2 times square root of 3

nydimaria [60]3 years ago
4 0
For this case what you should do is use the following trigonometric relationship:
 tan (x) = C.O / C.A
 Where
 x: angle
 C.O: opposite leg
 C.A: adjoining catheto
 Substituting the values we have:
 tan (60) = long / short
 tan (60) = long / 2
 long = 2 * tan (60)
 long = 3.46
 Answer: 
 long = 3.46
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Evaluate the summation of 3 n plus 2, from n equals 1 to 14..
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3 years ago
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LenaWriter [7]

Answer:

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Step-by-step explanation:

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Use the triangle below to find cos V.
Semenov [28]

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

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