Find 8x9. Use 2’s facts

you own a rectangular lot that id 500 feet deep it had an area of 1,000 square feet to pay for a new water system you are assess

poizon [28]

I’m pretty sure it’s is a 6’50

6 0

3 years ago

Estimation is best defined as: a. both a process of inferring the values of unknown samples statistics from those of known popul

Ghella [55]

Answer:

Option D is the correct answer - Estimation is best defined as a process of inferring the values of unknown samples statistics from those of known population parameters

Step-by-step explanation:

Estimation involves the usage of the value of a statistic derived from a sample to estimate the value of a corresponding population parameter.

The sample provides information that can be extended, through several formal or informal processes, to determine a range most suitable to describe the missing information.

An estimate that turns out to be incorrect would either be termed as over-estimation or under-estimation. If the estimate exceeds the actual result, it is termed as an over-estimation, and as an under-estimation, if the estimate came short of the actual result.

Thus, option D is correct.

8 0

3 years ago

Helppppppppppppppppp

Softa [21]

Answer:

CA = 32

Step-by-step explanation:

By intersecting chords theorem:

$12(4x + 1) = 14(3 + 3x) \\ \\ 48x + 12 = 42 + 42x \\ \\ 48x - 42x = 42 - 12 \\ \\ 6x = 30 \\ \\ x = \frac{30}{6} \\ \\ x = 5$

CA = 14 + ( 3 + 3x)

CA = 14 + ( 3 + 3*5)

CA = 14 + ( 3 + 15)

CA = 14 + 18

CA = 32

8 0

3 years ago

Isle Royale, an island in Lake Superior, has provided an important study site of wolves and their prey. Of special interest is t

STatiana [176]

Answer:

Part a) Probability that a moose in that age group is killed by a wolf

P (0.5 year) = 0.361

P (1 - 5) = 0.159

P (6 - 10) = 0.267

P (11 - 15) = 0.203

P (16 - 20) = 0.010

Part b)

Expected age of a moose killed by a wold

μ = 5.61 years

Stantard deviation of the ages

σ = 4.97 years

Explanation:

1) Start by arranging the table to interpret the information:

Age of Moose in years Number killed by woolves

Calf (0.5) 107

1 - 5 47

6 - 10 79

11 - 15 60

16 - 20 3

You can now verify the total number of moose deaths identified as wolf kills: 107 + 47 + 79 + 60 + 3 = 296, such as stated in the first part of the question.

2) First question: a) For each age, group, compute the probability that a moos in that age group is killed by a wolf.

i) Formula:

Probability = number of positive outcomes / total number of events.

ii) Probability that a moose in an age group is killed by a wolf = number of moose killed by a wolf in that age group / total number of moose deaths identified as wolf kills.

iii) P (0.5 year) = 107 / 296 = 0.361

iv) P (1 - 5) = 47 / 296 = 0.159

v) P (6 - 10) = 79 / 296 = 0.267

vi) P (11 - 15) = 60 / 296 = 0.203

vii) P (16 - 20) = 3 / 296 = 0.010

3) Second question: b) Consider all ages in a class equal to the class midpoint. Find the expected age of a moose killed by a wolf and the standard deviation of the ages.

i) Class midpoint

0.5 0.5

1 - 5 (1 + 5) / 2 = 3

6 - 10 (6 + 10) / 2 = 8

11 - 15 (11 + 15) / 2 = 13

16 - 20 (16 + 20) = 18

ii) Expected age of a moose killed by a wolf = mean of the distribution = μ

μ = Sum of the products of each probability times its age (mid point)

μ = 0.5 ( 0.361) + 3 ( 0.159) + 8 ( 0.267) + 13 ( 0.203) + 18 ( 0.010) = 5.61 years

μ = 5.61 years ← answer

iii) Stantard deviation of the ages = σ

σ = square root of the variace

variance = s = sum of the products of the squares of the differences between the mean and the class midpoint time the probability.

s = (0.5 - 5.61)² (0.361) + (3 - 5.61)² ( 0.159) + (8 - 5.61)² ( 0.267) + (13 - 5.61)² ( 0.203) + (18 - 5.61)² ( 0.010) = 24.65

σ = √ (24.65) = 4.97 years ← answer

7 0

3 years ago

Big Smiles Toy Company needs to pack marbles into a box. The company has two boxes they can use. Box A is 9 inches wide, 13 inch

shtirl [24]

Answer:

Big Smiles Toy Company should choose Box B as its volume is 82.5 $inch^3$ larger than Box A

Step-by-step explanation:

Given

Dimension of Box A= 9 inches width, 13 inches length, 11.5 inches height

Dimension of Box B =14 inches width, 8.5 inches length, 12 inches height

Volume of Box A= Length $\times$ width $\times$ height= $9\times13\times11.5= 1345.5 inches^3$

Volume of Box B =Length $\times$ width $\times$ height= $14\times8.5\times12= 1428 inches^3$

Difference = Volume of Box B - Volume of Box A = 1428 - 1345.5 = 82.5 $inches^3$

Box B has 82.5 $inch^3$ volume larger than Box A

4 0

3 years ago