The answer is A, you would plug in 3 for fx so therefore the answer would be A. Then to make sure plug in the other functions.:)
To make this easy let covert everything using a LCD.
The LCD of 1/4 1/12 and 1/6 is 12. This becomes...
Tom ate 3/12 of the pizza.
Leftover pizza = 9/12.
Slices were 1/12.
X friends got pizza.
Remaining pizza is 2/12.
if each friend got 1 piece(1/12)....
9/12(Leftovers) - 2/12(remaining) = 7/12
So 7 friends got pizza.
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
speed = distance/ time so:
(2/7) / (2/5) = (2/7) x (5/2) = 10/14 = 5/7 mph
5/7 = 0.71 miles per hour if you need decimal formatStep-by-step explanation:
