Question

In 5 minutes a conveyor belt moves 300 pounds of receyclable aluminum from the delievery truck a smaller belt moves the same quantitly of cans the same distance in 9 minutes if both belts are used find how long it takes to move the cans

Answer 1

Answer:

It will take 3.214 minutes.

Step-by-step explanation:

It is given that, the conveyor belt transports 300 cans in 5 mins and the smaller belt transports 300 cans in 9 minutes.

Thus , the speed of conveyor belt is,

= $\frac{300}{5} = 60 cans per minute$

and of smaller belt is,

=  $\frac{300}{9} = \frac{100}{3} cans per minute$

Thus, when both are used together,

conveyor belt will transport (60)(t) cans and smaller belt will transport $( \frac{100}{3})$(t) cans per minute.

Thus the equation becomes,

$300 = (60)(t) + (\frac{100}{3})(t) = (\frac{280}{3})(t)$

t = $\frac{(300)(3)}{280} = \frac{45}{14} = 3.214 minutes$