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Shkiper50 [21]
2 years ago
7

Round 653 , 500 653,500653, comma, 500 to the nearest thousand.

Mathematics
1 answer:
Jlenok [28]2 years ago
5 0

Answer:

Do you mean to round the number 653,500,653,500,653,500? Or do you mean to round the number 653,500? If so, for 653,500, the digit in the thousand's place is 5, so it's already rounded to the nearest thousands place.

Step-by-step explanation:

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Just answer the question below in the screenshot it!! Good luck!
8_murik_8 [283]

Answer:

it would be c

Step-by-step explanation:

4 0
3 years ago
How do you do inequalitys?
nata0808 [166]
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4 0
2 years ago
The table show the age in years of employees in a company
adelina 88 [10]

Answer:

A. 24 ≤ a < 26.

B. 22.5

Step-by-step explanation:

A. Determination of the modal class interval.

Mode is the class with the highest frequency.

From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:

24 ≤ a < 26.

B. To obtain the mean, we must determine the class mark. This is illustrated below:

Class >>>>> class mark >>> frequency

18 – 19 >>>> 18.5 >>>>>>>>> 3

20 – 21 >>> 20.5 >>>>>>>> 2

22 – 23 >>> 22.5 >>>>>>>> 7

24 – 25 >>> 24.5 >>>>>>>> 8

26 >>>>>>>> 26 >>>>>>>>> 0

The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:

Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)

Mean = (55.5 + 41 + 157.5 + 196 + 0)/20

Mean = 450/20

Mean = 22.5

Therefore, the mean age is 22.5

4 0
2 years ago
Read 2 more answers
Rewrite the rarional exponent as a radical by extending the properties of integer exponents
Nataly_w [17]

Answer: C

Step-by-step explanation:

Simplify the expression to 2^1/4

Now transform the expression using a^m/n = n root a raised to a power of m.

And that's how you get your answer.

3 0
3 years ago
Solve in radians help plz
PIT_PIT [208]
I think we can use the identity  sin x/2  = sqrt [(1 - cos x) /2]

cos x -  sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1

cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) =  cos x - 1   Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1

cos^2 x - 0.5 cos x - 0.5 = 0 

cos x = 1 , -0.5

giving x = 0 , 2pi, 2pi/3,  4pi/3  ( for  0  =< x <= 2pi)

because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.

The last 2 results dont fit so the answer is  x = 0 , 2pi Answer
5 0
3 years ago
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