I am assuming you want to find the simplest form of the inequality.
1.
2.
3.
1. Start
2. Subtract 9 from each side
3. Divide both sides by 3
Just look at it this way do 8(1) instead of x and graph that on the x axis
then do 4(1)instead of y and graph on the y axis then figure out which numbers you need to keep inputting until you reach 56 on the graph.
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer: 4. (-1,-1) 3. (3,-2)
4)
Set the equations equal to each other.
4x+3=-x-2
Subtract 3 from both sides
4x=-x-5
Add x to both sides
5x=-5
Divide both sides by 5
x=-1
Next, replace x with -1 in either equation to find y.
-(-1)-2=y
-1=y
3)
Do the same thing for this one and set them equal to each other
-2x+4=-1/3x-1
Add 1 to both sides
-2x+5=-1/3x
Add 2x to both sides
5=5/3x
Divide both sides by 5/3
x=3
Next, replace x with 3 in either equation
-2(3)+4=y
-2=y
