Answer:
Domain: [-6, 3, -4, 1]
Range: [3, -9, 1, -4]
Explanation:
if a particular relation is written as

the x is the input value and y is the output value.
The domain is defined as all possible input values a relation can take.
The range is defined as all possible output values a relation can take.
Now in our case, the relation we have is {(-6,3), (3,-9), (-4,1), (1,-4)}. Therefore, the all possible domain values we have are [-6, 3, -4, 1].
All output values that our relation can take are 3, -9, 1, and -4. Therefore, the range is [3, -9, 1, -4].
Hence, to summerise,
Domain: [-6, 3, -4, 1]
Range: [3, -9, 1, -4]
Answer: the rate of the river's current is 14 mph.
Step-by-step explanation:
Let x represent the rate of the river's current.
The speed of the motor boat in still water is 35 mph.
Since the boat travelled more miles downstream than upstream at the same time, it means that while going downstream, it moved in the direction of the current and while going upstream, it moved against the direction of the current. The total speed downstream would be
(35 + x) mph and the total speed upstream would be (35 - x) mph.
Time = distance/speed
If the boat can travel 7 miles downstream, the time spent travelling downstream is
7/(35 + x)
At the same time it takes to travel 3 miles upstream, the time spent travelling upstream is
3/(35 - x)
Since the time is the same, then
7/(35 + x) = 3/(35 - x)
Cross multiplying, it becomes
7(35 - x) = 3(35 + x)
245 - 7x = 105 + 3x
3x + 7x = 245 - 105
10x = 140
x = 140/10
x = 14
Answer:
B. 50 times greater
Step-by-step explanation:
Given;
size of phytoplankton = 2 × 10⁻⁶ in
size of sand grain = 1 × 10⁻⁴ in
Determine how many times longer the grain of sand is than the phytoplankton.
Divide the sand size by the phytoplankton size, to find out how much greater the sand is.
This can be done by equating it as follows;
2 × 10⁻⁶ (y) = 1 × 10⁻⁴

Therefore, the grain of sand is 50 times greater than the phytoplankton
B. 50 times greater