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suter [353]
3 years ago
6

Estimate the:length of a penlength of a swimming poollength of a marathon race​

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0
<h2><em><u>Answers</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>question</u></em><em><u>:</u></em></h2>

<h3><em><u>length</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>pen</u></em><em><u>:</u></em></h3>

5.2 inches 13.12 cm

<h3><em><u>length</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>swimming</u></em><em><u> </u></em><em><u>pool</u></em><em><u>:</u></em></h3>

50m

<h3><em><u>length</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>marathon</u></em><em><u> </u></em><em><u>race</u></em><em><u>:</u></em></h3>

42.195 kilometers

<h2>hope this answers your question! </h2>
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Step-by-step explanation:

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Which is an equation of the line that passes through the point (8,7) and is perpendicular to the line whose equation is y = 4x-1
algol [13]

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Step-by-step explanation:

7 0
3 years ago
Find the remaining trigonometric functions of θ based on the given information.csc θ = 257 and cos θ &lt; 0
katrin [286]
Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) = \frac{1}{sin(θ)} = 257
==> sin(<span>θ) = \frac{1}{257}
it is positive, so now we can determine that is in Quadrant 2

sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj: 257^{2} -  1^{2}  = adj ==\ \textgreater \  adj  \sqrt{ 257^{2} -   1^{2} } ==\ \textgreater \  adj = 16 \sqrt{258}

cosθ = \frac{16 \sqrt{258} }{257} &#10;
tanθ = \frac{1}{16 \sqrt{258} }
cos<span>θ = </span>16 \sqrt{258}
6 0
4 years ago
Can anyone please help me with this??????????? please please help me with this
Vanyuwa [196]
Congruent is the corrrect answer ya
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3 years ago
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