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Ad libitum [116K]
3 years ago
8

4x+5≤−4x Please I have been trying to do 1 step inequalities for hours

Mathematics
2 answers:
Sliva [168]3 years ago
7 0

Answer:

I'll keep calculating for this problem. but hope this can help you. but I'll keep calculating havea good day.

LUCKY_DIMON [66]3 years ago
7 0

Answer:

Step-by-step explanation:

4x + 5 ≤ - 4x

4x + 4x ≤ - 5

8x ≤ - 5

x ≤ - \frac{5}{8}

x ∈ ( - ∞ , - 0.625 ]

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Find the two partial products in this problem. <br> 1,407x14
Neporo4naja [7]

Answer:

<em>     1,407</em>

<em>x       14</em>

<em>_______</em>

<em>      5,628</em>

<em>+   1,4070</em>

<em>______</em>

  19,698

<em>The two partial products are 5,628 and 14,070</em>

7 0
3 years ago
Find the volume of a cube if an edge has length 4rst units
S_A_V [24]

Answer:

64

Step-by-step explanation:

4 * 4 * 4 = 64

5 0
3 years ago
Given the function defined in the table below, find the average rate of
AURORKA [14]

Answer:

Average rate of change = \frac{2}{5}

Step-by-step explanation:

Average rate of change of a function 'f' in the interval a ≤ x ≤ b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

We have to find the average rate of change in the interval 20 ≤ x ≤ 65

From the table attached,

f(65) = 32

f(20) = 14

Average rate of change = \frac{32-14}{65-20}

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Therefore, average rate of change in the given interval is \frac{2}{5} .

7 0
3 years ago
NEED ANSWER AS SOON AS POSSIBLE!!
umka21 [38]

Answer:

It's -8.

Step-by-step explanation:

The 5 in the f(5) is the 5 in the x column. Then you just find its value, which is -8

5 0
3 years ago
A math tutor earns $40 an hour tutoring teenagers. Sometimes he will meet with two students at once and get paid $80 per hour to
kati45 [8]

Answer:

It should be linear if you let the variable t represent the time tutoring for ONE student,   so   y = 40*t   where t = number of hours for ONE student

so  if the tutor taught  2 students for 2 hours together, then t = 2*2 = 4 hours

Step-by-step explanation:

y = 40t

t = tutoring hours for ONE unique student...

4 0
3 years ago
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