Racket : 94
balls : 12.50
warm ups : 34
shorts : 19.95
shoes : 44.50
total with tax : 204.95 + .05(204.95) = 204.95 + 10.25 = 215.20
20 per lesson for 12 lessons : 20 * 12 = 240
12 miles 1 way....thats 24 miles round trip, at 0.42 per mile : 24(0.42) =
10.08.....lessons and mileage : 240 + 10.08 = 250.08
for a total of : 215.20 + 250.08 = 465.28 <==
The gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².
<h3>What is the Total Surface Area of a Rectangular Box?</h3>
Total surface area (TSA) = 2(wl+hl+hw), where:
- l = length
- w = width
- h = height of the box.
The amount of gift wrap needed to cover the whole box = total surface area of the rectangular box
l = 20 in.
w = 8 in.
h = 13 in.
Plug in the values into the formula for total surface area of a rectangular box:
TSA = 2(8×20 + 13×20 + 13×8)
TSA = 1,048 in.²
Therefore, the gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².
Learn more about rectangular box on:
brainly.com/question/13103197
Answer: 2z-15
Step-by-step explanation
Based on the visual image, AD is a line where a point O intersects somewhere on the line. AD is represented as 3z-11, while the segment from AO is represented as z+4.
In order to find the answer, we must subtract the entire line (AD) from AO in order to find the missing segment OD.
AD - AO = OD
(3z-11) - (z+4) = OD
Distribute the negative sign so it becomes:
(3z-11) -z - 4 = OD
Now combine like terms.
(3z-z) +(- 11 -4)= OD
2z - 15 = OD
And that is your answer!
9514 1404 393
Answer:
x = 1 or 5
Step-by-step explanation:
The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

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<em>Comment on "cross multiply"</em>
Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.
What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.
