9514 1404 393
Answer:
$7.14
Step-by-step explanation:
Let p, d, q represent the numbers of pennies, dimes, and quarters in the collection, respectively.
p + d + q = 45 . . . . . . . . there are 45 coins in the collection
2p +5 = q . . . . . . . . . . . . 5 more than twice the number of pennies
p + 4 = d . . . . . . . . . . . . . 4 more than the number of pennies
Substituting the last two equations into the first gives ...
p +(p +4) +(2p +5) = 45
4p = 36 . . . . . . . . . . . . . subtract 9
p = 9 . . . . . . . . . . . divide by 4
d = 9 +4 = 13
q = 2(9) +5 = 23
The value of the collection is ...
23(0.25) +13(0.10) +9(0.01) = 5.75 +1.30 +0.09 = 7.14
The coin collection is worth $7.14.
Answer:
198 is the variance for the number of defective parts made each week.
Step-by-step explanation:
We are given the following in the question:
Number of parts produced each week = 20,000
Percentage of defective parts = 1%
We have to calculate the variance for the number of defective parts made each week.
We treat defective part as a success.
P(Defective part) = 1% = 0.01
Then the number defective parts follows a binomial distribution
.
Formula for variance =
Thus, 198 is the variance for the number of defective parts made each week.
Answer:
Wouldn't it be answer B?
Step-by-step explanation:
The rest of the answers have addition which is not in the problem provided.
