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2 years ago

Please help me guys !!!

Mathematics

1 answer:

Zolol [24]2 years ago

8 0

Answer: The 2nd one on your right

Step-by-step explanation:

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What is the square root of:<br><br>a) 58.82<br>b) 10

natka813 [3]

Square root of A= 7.66 ( Took the first 2 numbers after the decimal.)
Square root of B= 3.16 (Took the first 2 numbers after the decimal.)
HOPE THIS HELPS! ^_^

7 0

2 years ago

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago

A parabola has vertex (2, 3) and contains the point (0, 0). find an equation that represents this parabola.

AfilCa [17]

First write it in vertex form :-

y= a(x - 2)^2 + 3 where a is some constant.

We can find the value of a by substituting the point (0.0) into the equation:-

0 = a((-2)^2 + 3

4a = -3

a = -3/4

so our equation becomes y = (-3/4)(x - 2)^2 + 3

7 0

2 years ago

A number is one thousandth of 78,962. What is the number?

JulsSmile [24]

Answer:

78.962

Step-by-step explanation:

its just moving the decimal

5 0

3 years ago

Can any one help please :)

Gemiola [76]

Answer:

Step-by-step explanation:

First, subtract 3 by the numbers

-8 > 4x > 4

Remember to flip the inequality signs

Second, divide all the numbers by 4

-2 < x < 1

Flip the inequality signs again

-2 > x > 1

I am not very experienced with these problems so I might be wrong.

7 0

2 years ago

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