All categories

3 years ago

Let x = a + bi and y = c + di and z = f + gi

2 answers:

6 0

True statements:
a) x + y = y + x ⇒ commutative property of addition
b) (x * y) * z = x * (y * z) ⇒ associative property of multiplication
d) (x + y) + z = x + (y + z) ⇒ associative property of addition

False statements:
c) x - y = y - x should be: x - y = - y + x
e) (x - y) - z = x - (y - z) should be: (x - y) - z = x - (y + z)

Fynjy0 [20]3 years ago

5 0

Answer:

a x + y = y + x

b ( x * y ) * z = x * (y * z)

d ( x + y ) + z = x + ( y + z )

i just did it

Step-by-step explanation:

You might be interested in

In the general equation of a line, if A = 0, what will the graph of the line look like?

attashe74 [19]

It would be a zero slope

4 0

3 years ago

Read 2 more answers

We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab

777dan777 [17]

Answer:

(a) The distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

Step-by-step explanation:

It is provided that random variables $X_{i}$ are independent and identically distributed Bernoulli random variables with p = 0.50.

The random sample selected is of size, n = 100.

(a)

Theorem:

Let $X_{1},\ X_{2},\ X_{3},...\ X_{n}$ be independent Bernoulli random variables, each with parameter p, then the sum of of thee random variables, $X=X_{1}+X_{2}+X_{3}...+X_{n}$ is a Binomial random variable with parameter n and p.

Thus, the distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

The sample size is large, i.e. n = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu=p=0.50$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05$

(c)

Compute the value of $P(\bar X>0.50)$ as follows:

$P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\$

$=P(Z>0)\\=1-P(Z$

*Use a z-table.

Thus, the value of $P(\bar X>0.50)$ is 0.50.

8 0

3 years ago

2(2x-3) + 3(x + 1) = 5x +2

Lerok [7]

X=5/2 , remove parentheses , collect like terms, move terms , collect like terms and calculate the sum , then divide both sides by 2 , hope this helped broski

5 0

3 years ago

Read 2 more answers

A square sheet of paper measures 42 centimeters on each side. What is the length of the diagonal of this paper?

Illusion [34]

59.4cm
Use Pythagorean theorem to find the diagonal (^ means exponent)
a^2 + b^2 = c^2
42^2 + 42^2= c^2
1764+1764=c^2
3528=c^2
square root both sides
c= 59.39696962
round and you get 59.4 cm

5 0

3 years ago

What does it mean to multiply fractions?

Anastasy [175]

to put them together and add them.

7 0

3 years ago

Read 2 more answers