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3 years ago

8

Let x = a + bi and y = c + di and z = f + gi

2 answers:

ikadub [295]3 years ago

6 0

True statements:
a) x + y = y + x ⇒ commutative property of addition
b) (x * y) * z = x * (y * z) ⇒ associative property of multiplication
d) (x + y) + z = x + (y + z) ⇒ associative property of addition

False statements:
c) x - y = y - x should be: x - y = - y + x
e) (x - y) - z = x - (y - z) should be: (x - y) - z = x - (y + z)

Fynjy0 [20]3 years ago

5 0

Answer:

a x + y = y + x

b ( x * y ) * z = x * (y * z)

d ( x + y ) + z = x + ( y + z )

i just did it

Step-by-step explanation:

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Please help me ill mark you as brainiset

Artyom0805 [142]

Answer: -$560

Step-by-step explanation: Ahem, So basically u divide -$5040 by 9 months and then you get -$560

Plz mark me brainliest it would mean so much! :)

8 0

2 years ago

Which products result in a perfect square trinomial? Select three options.

Kazeer [188]

Answer:

Second option: $(xy+x)(xy+x)$

Third option: $(2x-3)(-3+2x)$

Fifth option: $(4y^2+25)(25+4y^2)$

Step-by-step explanation:

By definition, a perfect square trinomial can be obtained by squaring binomials.

Then:

$(a+b)^2=(a+b)(a+b)=a^2+2ab+b^2\\\\(a-b)^2=(a-b)(a-b)=a^2-2ab+b^2$

Knowing this, to obtain a perfect square trinomial, the binomials that you multiply must be equals.

Therefore, the products result in a perfect square trinomial are:

$(xy+x)(xy+x)=(xy+x)^2=(xy)^2+2(xy)(x)+x^2=x^2y^2+2x^2y+x^2$

$(2x-3)(-3+2x)=(2x-3)^2=(2x)^2-2(2x)(3)+3^2=4x^2-12x+9$

$(4y^2+25)(25+4y^2)=(4y^2+25)^2=(4y^2)^2+2(4y^2)(25)+25^2=16y^4+200y^2+625$

8 0

3 years ago

Read 2 more answers

Solve the inequality 13 > 3x + 1

Ivenika [448]

4 > x

step by step explanation:

13 > 3x + 1
-1 -1
12 > 3x
/3 /3
4 > x

3 0

3 years ago

Read 2 more answers

What are the first three terms of the Arithmetic Sequence an = 11 – 3(n – 1)?

vaieri [72.5K]

Answer:First three terms: 11,20,29 .

Step-by-step explanation:

Write a systems of equations. tn=a+(n−1)d. sn=n2 (2a+(n−1)d). So,. 110=11+(n−1)d 726=n2(22+(n−1)d).

I hope this is right

3 0

3 years ago

The sum of the first three terms of a sequence is 6 and the fourth term is 16

Sati [7]

Answer:

a₁ = -5, d = 7, a₂ = 2, a₃ = 9, a₄ = 16

equation of sequence: $\boxed{\bold{a_n=7n-12}}$

Step-by-step explanation:

a₁ + a₂ + a₃ = 6

a₁ + a₁ + d + a₁ + 2d = 6

3a₁ + 3d = 6

a₁ + d= 2 ⇒ a₁ = 2 - d

a₄ = 16

a₁ + 3d = 16

2 - r + 3d = 16

2d = 14

d = 7

a₁ = 2-7 = -5

a₁ = -5, d = 7 ⇒ a₂ = -5+7 = 2, a₃ = 2+7 = 9, a₄ = 9+7 = 16

equation of arithmetic sequence:

$a_n=a_1+d(n-1)\\\\a_n=-5+7(n-1)\\\\\underline{a_n=7n-12}$

6 0

3 years ago