Based on the calculations, the solubility of PbCrO₄ in water at at 25°C is equal to 1.4 x 10⁻⁸ M.
<h3>How to calculate the solubility of PbSO₄?</h3>
The properly balanced chemical equation for the dissociation of PbSO₄ is given by:
PbCrO₄(s) ⇆ Pb²⁺(aq) + CrO₄²⁻(aq)
Initial 0 0
Change +x +x
Equib. conc. x x
<u>Note:</u> The Ksp of PbCrO₄ at 25°C is equal to 2.0 × 10⁻¹⁶.
Next, we would set up an equation from the ICE table for its Ksp;
Ksp = [Pb²⁺][CrO₄²⁻]
2.0 × 10⁻¹⁶ = [x][x]
2.0 × 10⁻¹⁶ = x²
x = √2.0 x 10⁻¹⁶
x = 1.4 x 10⁻⁸ M.
Read more on solubility here: brainly.com/question/15396081
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Explanation:
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