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3 years ago

Please help me on dis question

Mathematics

1 answer:

lara [203]3 years ago

5 0

Answer:

a) See below

b) $\huge\boxed{\sf Area\ of\ each\ triangle = 62.4\ in.\²}$

c) $\huge\boxed{\sf Area\ of\ the\ table = 374.4\ in.\²}$

Step-by-step explanation:

We can draw 3 lines from A to D, B to E and F to C such that all of the lines pass from the center. This will form 6 equal (congruent) triangles.

$\rule[225]{225}{2}$

Area of each triangle = 1/2 (Base)(Height)

Where Base = 12 in. and Height = 10.4 in.

Area = 1/2 (12) (10.4)

Area = 6 (10.4)

Area of each triangle = 62.4 in.²

$\rule[225]{225}{2}$

Since the table is mage up of 6 equal triangles:

So,

Area of the table = 6 (Area of each triangle)

Area of the table = 6 (62.4)

Area of the table = 374.4 in.²

$\rule[225]{225}{2}$

Hope this helped!

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If y varies directly and y is 12 when x is 1.2 what is the constant of variation for this relation

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Step-by-step explanation:

(a) For using Cramer's rule you need to find matrix $A$ and the matrix $B_j$ for each variable. The matrix $A$ is formed with the coefficients of the variables in the system. The first step is to accommodate the equations, one under the other, to get $A$ more easily.

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Here is your answer in the attachment.

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