Question

What are the solutions of 3x^2 + 14x + 16 = 0?

Answer 1

The solution is :
x= -8/3 , -2

Answer 2

Answer:

The correct option is A) x = -8/3, –2.

Step-by-step explanation:

Consider the provided equation $3x^2 + 14x + 16 = 0$

The above equation is in the form of $ax^2 +bx + c = 0$

The quadratic formula to find the root of the equation is:

${\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}\ \ }$

By comparing the above equation with the general equation we can conclude that:

a = 3, b = 14, and c = 16

Substitute the respective values in the above formula:

${\displaystyle x={\frac {-14\pm {\sqrt {14^{2}-4(3)(16)}}}{2(3)}}\ \ }$

${\displaystyle x={\frac {-14\pm {\sqrt {196-192}}}{6}}\ \ }$

${\displaystyle x={\frac {-14\pm {\sqrt {4}}}{6}}\ \ }$

${\displaystyle x={\frac {-14\pm2}{6}}\ \ }$

${\displaystyle x={\frac {-14+2}{6}}\ \ } or\ {\displaystyle x={\frac {-14-2}{6}}\ \ }$

${\displaystyle x={\frac {-12}{6}}\ \ } or\ {\displaystyle x={\frac {-16}{6}}\ \ }$

${\displaystyle x=-2}\ \ } or\ {\displaystyle x={\frac {-8}{3}}\ \ }$

Hence the solutions of the provided equation is ${\displaystyle x=-2}\ \ } or\ {\displaystyle x={\frac {-8}{3}}\ \ }$.

Thus, the correct option is A) x = -8/3, –2.