Answer:
A. 121 ⇒ III. 11
B. 64 ⇒ II. 4 and IV. 8
C. 27 ⇒ I. 3
D. 125 ⇒ V. 5
E. 16 ⇒ II. 4
Step-by-step explanation:
Let us find the correct answer
∵ 121 = 11 × 11
∴ The square root 121 is 11
∴ A. 121 ⇒ III. 11
∵ 64 = 8 × 8
∴ The square root of 64 is 8
∵ 64 = 4 × 4 × 4
∴ The cube root of 64 is 4
∴ B. 64 ⇒ II. 4 and IV. 8
∵ 27 = 3 × 3 × 3
∴ The cube root of 27 is 3
∴ C. 27 ⇒ I. 3
∵ 125 = 5 × 5 × 5
∴ The cube root of 125 is 5
∴ D. 125 ⇒ V. 5
∵ 16 = 4 × 4
∴ The square root of 16 is 4
∴ E. 16 ⇒ II. 4
I'm pretty sure it's 28 but sorry if I'm wrong it might be 44
Answer is D hope it helps
Answer:
18.67% probability that the sample proportion does not exceed 0.1
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
For the sampling distribution of a sample proportion, we have that 
In this problem, we have that:

What is the probability that the sample proportion does not exceed 0.1
This is the pvalue of Z when X = 0.1. So



has a pvalue of 0.1867
18.67% probability that the sample proportion does not exceed 0.1
Answer:
Step-by-step explanation:
15) should be b) 6.7, 6 as the median is the average of the 25th and 26th result, these both occur in the 6 group and is the only option with a whole number for median
To check the mean
(2(4) + 7(5) + 17(6) + 10(7) + 8(8) + 6(9)) / 50 = 6.66 ≈ 6.7
16) mode is 1 child as the single largest grouping is 11 families
there were 46 families polled so the median occurs between 23 and 24
7 + 11 + 6 is 24 therefore median falls under 2 children.
a) 1, 2