Question

Graph the function Need help ASAP plz

Answer 1

Given:

The equation of a function is

$y=(x-4)^2+1$

To find:

The graph of the given function.

Solution:

The vertex form of a parabola is

$y=(x-h)^2+k$        ...(i)

Where, (h,k) is vertex of the parabola.

We have,

$y=(x-4)^2+1$         ...(ii)

From (i) and (ii), we get

$h=4, k=1$

The vertex of the parabola is (4,1).

Now, the table of values is

x             y

2            5

3            2

4             1

5            2

6            5

Plot these points on a coordinate plane and connect them by a free hand curve.

The graph of given function is shown below.