<u>Answer:</u>
The available amount for the down payment of car and invested $3,200 at 3.75% interest compounded continuously is 3449.23$
<u>Explanation:</u>
We know final amount is given by
Where,

A = final amount
P = initial principal balance = $3200
r = interest rate = 3.74%
t = number of time periods elapsed = 2 years
Substituting the values in the formula

A=
We know, e = 2.72
So we get A = 3449.23$ which is the available amount for the down payment of car .
Answer: see below
Step-by-step explanation:
The shape is a trapezoid
Base 1 (BH) is 10
Base 2 (QA) is 14
Height is 5
Area


Find distance between QB and HA

Q( -4,4) B (-2,9)

Perimeter
Answer:
correct option is d. $242.81
Step-by-step explanation:
given data
APR = 25.5% =
= 2.125
paid = $3,729
solution
we get here finance charge on the 1st month by multiplying 3,729 and now adding it to existing balance
so we get finance charge for the second and third months similarly as
APR ÷ 100 =
= 0.02125
so 1st
= $3,729 × 0.02125
= 79.25
and
$3,729 + $79.25 = $3808.24
so for next
= $3808.24 × 0.02125
= 80.93
and
$3808.24 + $80.93 = $3889.17
so for next
= $3889.17 × 0.02125
= 82.64
and
$3889.17 + $ 82.64 = $3971.81
so
finance
charge = 3971.81 - 3729
finance
charge = 242.81
so correct option is d. $242.81